July 2021 0 12 Report
В равнобокой трапеции АВСD угол А = 75 градусов, диаганали AC и BD пересекаются в точке О, СЕ перпендикулярен АD, СЕ=АЕ, BO=5. Найти боковые стороны данной трапеции.
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