n(CO2) = 1,204·10²³/6,02·10²³ = 0,2(моль)
V(CO2) = 22,4·0,2 = 4,48 (л)
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n(CO2) = 1,204·10²³/6,02·10²³ = 0,2(моль)
V(CO2) = 22,4·0,2 = 4,48 (л)