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evgen22region
@evgen22region
July 2022
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В сосуд, содержащий лед массой m при температуре 0........................
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alaswalkman
Q1 - Q2 = dQ
dm = 1.1
m2 = 1
t1 = 0
t2 = 70
L= 330000
c= 4200
dt = (70- 0)= 70
m1-?
m1*L - m2*c*dt = dm*L
m1 =(dm*L + m2*c*dt)/L= 1.99 кг
ответ : 1.9909 кг приблизительно :2 кг
3 votes
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Answers & Comments
dm = 1.1
m2 = 1
t1 = 0
t2 = 70
L= 330000
c= 4200
dt = (70- 0)= 70
m1-?
m1*L - m2*c*dt = dm*L
m1 =(dm*L + m2*c*dt)/L= 1.99 кг
ответ : 1.9909 кг приблизительно :2 кг