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FolianRaist
@FolianRaist
July 2022
1
5
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В трапеции
ABCD
AD=3
,
BC=1
, а её площадь равна 12. Найдите площадь треугольника
ABC
.
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malutarad
Verified answer
S=(BC+AD)/2*CH, 12=(1+3)/2*CH, CH=6,
S ACD=AD*CH/2=3*6/2=9
S АВС= SABCD-SACD=12-9=3
248 votes
Thanks 645
fghy266
а если те же данные но площадь будет равна 48
fghy266
то как будет решаться
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Verified answer
S=(BC+AD)/2*CH, 12=(1+3)/2*CH, CH=6,S ACD=AD*CH/2=3*6/2=9
S АВС= SABCD-SACD=12-9=3