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kot59
@kot59
July 2022
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в треуг.АВС, уголС= 90градусов, АС =12, cosА=корень 51на 10.найти высоту СН.
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vika5612
СН/AC=sinA
CH=AC*sinA
sin2 A=1-cos2 A = 1-( √15/10)^2 = 1-0,15 = 0,85
sinA= √0,85
СН=12* √0,85 ≈ 11
Ответ: СН=11
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Answers & Comments
CH=AC*sinAsin2 A=1-cos2 A = 1-( √15/10)^2 = 1-0,15 = 0,85
sinA= √0,85
СН=12* √0,85 ≈ 11
Ответ: СН=11