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Azoma11
@Azoma11
July 2022
1
8
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В треугольника ABC <C=90,sinA=0,8 ; AC=6 . Найдите AB
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AkiraHino
CosA^2=sinA^2=1^2
cosA^2+0.8^2=1^2
cosA^2+0.64=1^2
cosA=
√1-0,64
cosA=√0,36
cosA=0,6
AC/AB=0,6
6/AB=0,6
AB=10
Ответ: 10
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Answers & Comments
cosA^2+0.8^2=1^2
cosA^2+0.64=1^2
cosA=√1-0,64
cosA=√0,36
cosA=0,6
AC/AB=0,6
6/AB=0,6
AB=10
Ответ: 10