по теореме синусов из тр. ABC:
BC/sin (BAC)=AC/sin(ABC)
итого: sin(BAC)=BC*sin (ABC)/AC
sin(BAC)=(5*0.6/9)=1/3
good luck :)
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по теореме синусов из тр. ABC:
BC/sin (BAC)=AC/sin(ABC)
итого: sin(BAC)=BC*sin (ABC)/AC
sin(BAC)=(5*0.6/9)=1/3
good luck :)