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nitrogen002
@nitrogen002
June 2022
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В треугольнике ABC стороны AC и BC равны 5 AB = 2 √ 21 найдите sin A
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oganesbagoyan
Verified answer
AC =CB =5 ; AB =2√21 ;
-----------------------------
sinA--> ?
Проведем СH
⊥AB . Получается :
AH =BH =AB/2=2√21/2 =√21.
Из ΔAHC : sinA =AH/AC =√21/5
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Answers & Comments
Verified answer
AC =CB =5 ; AB =2√21 ;-----------------------------
sinA--> ?
Проведем СH ⊥AB . Получается : AH =BH =AB/2=2√21/2 =√21.
Из ΔAHC : sinA =AH/AC =√21/5