В треугольнике ABC угол C равен 90, AB = 12, AC = 6sqrt3. Найдите sin A
sinA = BC/AB;
BC = sqrt(AB^2 - AC^2);
BC = sqrt(144-108) = sqrt(36) = 6.
sinA = 6/12 = 0.5
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sinA = BC/AB;
BC = sqrt(AB^2 - AC^2);
BC = sqrt(144-108) = sqrt(36) = 6.
sinA = 6/12 = 0.5