В треугольнике ABC угол C равен 90° , AB = 20, AC = 10√3.Найдите sinA
sinA = BC/ABBC^2 = AB^2 - BC^2 = 400 - 300 = 100BC = 10sinA = 10/20 = 0.5
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
sinA = BC/AB
BC^2 = AB^2 - BC^2 = 400 - 300 = 100
BC = 10
sinA = 10/20 = 0.5