В треугольнике ABC угол С=90 градусов, СH - высота, BC=5, sinA=0,2. Найдите BH.. Created by julidura. matematika-ru

В треугольнике ABC угол С=90 градусов, СH - высота, BC=5, sinA=0,2. Найдите BH...

julidura @julidura

July 2022 1 29 Report

В треугольнике ABC угол С=90 градусов, СH - высота, BC=5, sinA=0,2. Найдите BH.

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NNNLLL54

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$sinA=\frac {BC}{AB}\\\\AB=\frac{BC}{sinA}=\frac{5}{0,2}=25\\\\AC=\sqrt{25^2-5^2}=\sqrt{600}=10\sqrt6\\\\sinA=\frac{CH}{AC}\\\\CH=AC\cdot ainA=10\sqrt6\cdot 0,2=2\sqrt6$

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