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govtvyan2000
@govtvyan2000
July 2022
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В треугольнике ABC=AC=BC=1, угол с=45.Найти сторону AB.ОЧЕНЬ СРОЧНО ПЖЖЖЖЖЖЖ
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kirichekov
Verified answer
ΔАВС: АС=ВС=1, <C=45°
по теореме косинусов:
AB²=AC²+BC²-2*AB*BC*cos<C
AB²=1²+1²-2*1*1*(√2/2)
AB²=2-√2
AB=√(2-√2)
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Answers & Comments
Verified answer
ΔАВС: АС=ВС=1, <C=45°по теореме косинусов:
AB²=AC²+BC²-2*AB*BC*cos<C
AB²=1²+1²-2*1*1*(√2/2)
AB²=2-√2
AB=√(2-√2)