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Maik54
@Maik54
June 2022
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в треугольнике АВС <В= 70° <С=75°, ВВ1 - биссектриса треугольника АВС, ВВ1=9см. Найдите длину отрезка АВ1
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kprof
∠A = 180-70-75=35
∠BB1C = 180 - ∠B/2 - ∠C = 180-35-75= 70
∠BB1A = 180-110= 70
По теореме синусов:
BB1/sin∠A = AB1/sin∠ABB1
AB1 = 9*sin70/sin35 = 9*0.9397/0.5736=14.74
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Answers & Comments
∠BB1C = 180 - ∠B/2 - ∠C = 180-35-75= 70
∠BB1A = 180-110= 70
По теореме синусов:
BB1/sin∠A = AB1/sin∠ABB1
AB1 = 9*sin70/sin35 = 9*0.9397/0.5736=14.74