sin∠B=AC/AB sin∠B=5/13
tg∠A=sin∠A/cos∠A
cos∠A=AC/AB cos∠A=5/13
sin∠A=√(1-cos²∠A) sin∠A=√(1-25/169)=√144/169=12/13
tg∠A=12/13÷5/13=12/5=2,4
можно найти tg и таким способом
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
sin∠B=AC/AB sin∠B=5/13
tg∠A=sin∠A/cos∠A
cos∠A=AC/AB cos∠A=5/13
sin∠A=√(1-cos²∠A) sin∠A=√(1-25/169)=√144/169=12/13
tg∠A=12/13÷5/13=12/5=2,4
можно найти tg и таким способом