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JoBarbara
@JoBarbara
October 2021
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в треугольнике даны угла abc угол b 80 градусов сторона bc10 ac25 найти угол a
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Dимасuk
Verified answer
По теореме синусов:
AC/sinB = BC/sinA, отквда sinA = BC•sinB/AC
sin80° ≈0,9848
sinA = 10•0,9848/25 ≈ 0,3939
arcsinA =23°12'.
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Answers & Comments
Verified answer
По теореме синусов:AC/sinB = BC/sinA, отквда sinA = BC•sinB/AC
sin80° ≈0,9848
sinA = 10•0,9848/25 ≈ 0,3939
arcsinA =23°12'.