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natchiy03
@natchiy03
August 2022
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в треугольнике MPK MP=PK а высота MH делит сторону PK на отрезки PH=8 HK=8. Найдите cos∠P
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ЯЖёнок
МР=РК⇒ ΔМРК-РАВНОБЕДРЕННЫЙ
РК=РН+НК=16
РК=МР=16
МР²=РН²+МН²
МН²=МР²-РН²=16²-8²
МН=√256-64=√192=8√3
соs∠Р= МН/
РН=8
√3/8=√3
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Answers & Comments
РК=РН+НК=16
РК=МР=16
МР²=РН²+МН²
МН²=МР²-РН²=16²-8²
МН=√256-64=√192=8√3
соs∠Р= МН/РН=8√3/8=√3