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iittlefox
@iittlefox
August 2022
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В треугольнике стороны 4, 5 и 6. Найдите cos угла лежащего напротив меньшей стороны.
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sova761
А^2=в^2+с^2-2вс
[email protected]
[email protected]
=(b^2+c^2-a^2)/2bc
[email protected]
=(6^2+5^2-4^2)/2·6·5=45/60=3/4=0,75.
ответ: 0,75
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Answers & Comments
[email protected]=(b^2+c^2-a^2)/2bc
[email protected]=(6^2+5^2-4^2)/2·6·5=45/60=3/4=0,75.
ответ: 0,75