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ChutChutTupas
@ChutChutTupas
July 2022
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В воде массой 180 г растворили соду массой 20 г. Определить массовую долю растворённого вещества
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wbdisdi
Дано:
m(H₂O) = 180г
+m(cодa) = 20г
Найти:
w(cодa)
Решение:
w(cодa) = 20/200
=0,1∗100
=0,1∗100
% =10%
Ответ: w(cодa) = 10%
28 votes
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Answers & Comments
m(H₂O) = 180г
+m(cодa) = 20г
Найти:
w(cодa)
Решение:
w(cодa) = 20/200=0,1∗100=0,1∗100% =10%
Ответ: w(cодa) = 10%