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vmnew
@vmnew
March 2022
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в выражении 2х^2 -7х+3 выделить квадрат двучлена и найти наименьшее значение выражения
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sangers1959
Verified answer
2x²-7x+3=(2x²-8x+8)+x-5=2*(x²-4x+4)+x-5=
2*(x-2)²+x-5
.
y`=(2x²-7x+3)`=4x-7=0
4x=7 |÷4
x=7/4=1,75 ⇒
ymin
=2*(1,75)²-7*(1,75)+3=6,125-12,25+3=-6,125+3=
-3,125.
3 votes
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Answers & Comments
Verified answer
2x²-7x+3=(2x²-8x+8)+x-5=2*(x²-4x+4)+x-5=2*(x-2)²+x-5.y`=(2x²-7x+3)`=4x-7=0
4x=7 |÷4
x=7/4=1,75 ⇒
ymin=2*(1,75)²-7*(1,75)+3=6,125-12,25+3=-6,125+3=-3,125.