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Alinaname
@Alinaname
July 2022
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В13. Длина вектора альфа равна 26
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nikolson93
J - лямбда
Ja (J*5;J*12)
IJaI^2 = 25*J^2 + 144*J^2= 169*J^2=676
J^2=4
J1=2 J2=-2
Ответ: наименьшее значение J= -2
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Answers & Comments
Ja (J*5;J*12)
IJaI^2 = 25*J^2 + 144*J^2= 169*J^2=676
J^2=4
J1=2 J2=-2
Ответ: наименьшее значение J= -2