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лиза1958
@лиза1958
August 2022
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(в^2-3)^3-(в^2+3)(в^4-3в^2+9)
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Arkadiя
(b²-3)³-(b²-3)(b^4-3b²+9)=(b²)³-3*b²*3+3*b*3²-3³-((b²)³+3³)=(b²)³-9b²+27b-9-(b²)³-9=-9b²+27b-18
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