Вариант 1, задание 3 под Б Даю 76 баллов...

zhiharevkirill0 @zhiharevkirill0

June 2022 1 12 Report

Вариант 1, задание 3 под Б
Даю 76 баллов

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NNNLLL54

Verified answer

$\Big(\dfrac{1}{4x^2}-\dfrac{1}{xy}+\dfrac{1}{y^2}\Big)\cdot \Big(\dfrac{1}{2x-y}-\dfrac{1}{y-2x}\Big)-\dfrac{1}{xy^2}=\\\\\\=\dfrac{y^2-4xy+4x^2}{4x^2y^2}\cdot \dfrac{-1-1}{y-2x}=\dfrac{(y-2x)^2}{4x^2y^2}\cdot \dfrac{-2}{y-2x}=\dfrac{-2(y-2x)}{4x^2y^2}=\dfrac{2x-y}{2x^2y^2}$

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