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denzodov
@denzodov
August 2022
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Вариант 3 номера 1,2,5 решите пожалуйста
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кирилл3445342543
1) n=m/Mr=54/18=3 моль
2) Mr(СН4)= 12+4*1=16
w(c)=12/16100%=75%
w(h)=4/16*100%=25%
Mr(C2H6)= 12*2+6*1=30
w(c)=24/30*100%=80%
w(h)=6/30*100%=20%
В метане больше
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кирилл3445342543
2H20=2H2+O2, 3*2/1=6 МОЛЬ воды, m=6*18=108 гр
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Answers & Comments
2) Mr(СН4)= 12+4*1=16
w(c)=12/16100%=75%
w(h)=4/16*100%=25%
Mr(C2H6)= 12*2+6*1=30
w(c)=24/30*100%=80%
w(h)=6/30*100%=20%
В метане больше