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1111305
@1111305
April 2021
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вариант 4 ,задание 5
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zzKarinazz
1)2HNO₃ + Pb = Pb(NO₃)₂ + H₂
∨(ню)(Pb) = ∨(ню)(H₂) = 0,03 моль
V(H₂) = 0,03*22,4 =0,672 л
V(н.у) =22,4 л/моль
Ответ: 0,672 л
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Answers & Comments
∨(ню)(Pb) = ∨(ню)(H₂) = 0,03 моль
V(H₂) = 0,03*22,4 =0,672 л
V(н.у) =22,4 л/моль
Ответ: 0,672 л