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Лулу52807
@Лулу52807
May 2022
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V(Cl2) = 5 л. Найти V (KCL)?
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anassstass
2K + Cl2 — 2KCl
V (Cl2) = 5 л
n (Cl2) = V/Vm = 5/22,4 = 0,22 моль
n (KCl) = 0,22*2/1 = 0,44 моль
V (KCl) = Vm*n = 22,4*0,44 = 9,856 л
Ответ: 9,856 л
2 votes
Thanks 1
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Answers & Comments
V (Cl2) = 5 л
n (Cl2) = V/Vm = 5/22,4 = 0,22 моль
n (KCl) = 0,22*2/1 = 0,44 моль
V (KCl) = Vm*n = 22,4*0,44 = 9,856 л
Ответ: 9,856 л