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jdjd7
@jdjd7
August 2022
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В)(х-2)(3х-5)=0 Г)(х-3)(х+3)=2 Д)(х-1)квадрат=2х+4
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NadezhdaAlexandrowna
В)(х-2)(3х-5)=0
3х²-5х-6х+10=0
3х²-11х+10=0
D=121-120=1(√1=1)
x1=(11+1)/2=6
x2=(11-1)/2=5
г)(х-3)(х+3)=2
х²-9=2
х²=11
х1,2=±√11
д) (х-1)²=2х+4
х²-2х+1=2х+4
х²-4х-3=0
D=16+12=26 (√26)
x1=(4-√26)/2
x2=(4+√26)/2
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Answers & Comments
3х²-5х-6х+10=0
3х²-11х+10=0
D=121-120=1(√1=1)
x1=(11+1)/2=6
x2=(11-1)/2=5
г)(х-3)(х+3)=2
х²-9=2
х²=11
х1,2=±√11
д) (х-1)²=2х+4
х²-2х+1=2х+4
х²-4х-3=0
D=16+12=26 (√26)
x1=(4-√26)/2
x2=(4+√26)/2