Ответ:
а)cos²Alfa
б)sin²alfa
в)sin²alfa
г)-5sin²beta
1) =
2) =
3) =
4)
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
а)cos²Alfa
б)sin²alfa
в)sin²alfa
г)-5sin²beta
Ответ:
1)
=
2)
=
3)
=
4)