дано
W(C) = 92.3 % = 0.923
M(CxHy) = 78 g/mol
-------------------------
CxHy-?
W(H) = 1-0.923 = 0.077
CxHy / 78 = 0.923 / 12 : 0.077 / 1
CxHy = 6 : 6
C6H6
ответ БЕНЗОЛ
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Verified answer
дано
W(C) = 92.3 % = 0.923
M(CxHy) = 78 g/mol
-------------------------
CxHy-?
W(H) = 1-0.923 = 0.077
CxHy / 78 = 0.923 / 12 : 0.077 / 1
CxHy = 6 : 6
C6H6
ответ БЕНЗОЛ