Ответ:

дано

W(C) = 92.3%

W(H) = 7.7%

V(CxHy) = 1 L

m(CxHy) = 1.16 g

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CxHy - ?

CxHy = 92.3 / 12 : 7.7 / 1 = 1 : 1  ==> CH

Vm = 22.4 l/mol

M(CxHy) = Vm * m(CxHy) / V(CxHy) = 22.4*1.16 / 1 = 26 g/mol

M(CH) = 13 g/mol

M(CxHy) / M(CH = 26 / 13 = 2

M(CxHy) = M(CH) * 2 = C2H2

ответ C2H2

Объяснение: