Ответ:
дано
W(C) = 72%
W(H) = 12%
-------------------
CxHyOz - ?
W(O) = 100% - ( W(C) + W(H)) = 100 - (72+12) =16%
m(C) = 72 g M(C) = 12 g/mol
m(H) = 12 g M(H) = 1 g/mol
m(O) = 16 g M(O) = 16 g/mol
CxHyOz = 72 / 12 : 12 /1: 16/ 16 = 6 :12:1
C6H12O
ответ : C6H12O
Объяснение:
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Ответ:
дано
W(C) = 72%
W(H) = 12%
-------------------
CxHyOz - ?
W(O) = 100% - ( W(C) + W(H)) = 100 - (72+12) =16%
m(C) = 72 g M(C) = 12 g/mol
m(H) = 12 g M(H) = 1 g/mol
m(O) = 16 g M(O) = 16 g/mol
CxHyOz = 72 / 12 : 12 /1: 16/ 16 = 6 :12:1
C6H12O
ответ : C6H12O
Объяснение: