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223marik223
@223marik223
August 2022
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Визнач масу 179,2 л (н.у.) етилену:
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PegeJ
Ответ:
m(C2H4)=V:Vm×M=179,2:22,4×28=224грамма
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Ответ:
m(C2H4)=V:Vm×M=179,2:22,4×28=224грамма