n(Li2CO3) = 6
m(Li2CO3) =?
m = n*M = 6*74 = 444г
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M (Li2CO3) = 7*2 + 12 + 16*3 = 14 + 12 + 48 = 74 г/моль
n = m/M
m(Li2CO3) = n * M = 6 * 74 = 444г
Ответ: 444г
n(Li2CO3) = 6
m(Li2CO3) =?
m = n*M = 6*74 = 444г