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nataart77
@nataart77
July 2022
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визначити об'єм водню який витратиться на гідрування 3 олеату масою 200г
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marichka111
200г
h2c-o-co-c17h33 xл h2c-o-co-c17h35
hc-o-co-c17h33 + 3h2 ---> hc-o-co-c17h35
h2c-o-co-c17h33 22,4 x 3 h2c-o-co-c17h35
880
200* 22.4 * 3 / 880 = 15.2 л
1 votes
Thanks 1
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Answers & Comments
h2c-o-co-c17h33 xл h2c-o-co-c17h35
hc-o-co-c17h33 + 3h2 ---> hc-o-co-c17h35
h2c-o-co-c17h33 22,4 x 3 h2c-o-co-c17h35
880
200* 22.4 * 3 / 880 = 15.2 л