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qazwsxedc86
@qazwsxedc86
August 2021
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визначити об'єм займає 2 г карбону (iv) оксиду
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ellliz1
V=n*Vm
M(CO2)=12+16*2=44 г/моль
n(CO2)=2/44=0,045 моль
V(CO2)=0,045*22,4=1,008 л
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Answers & Comments
M(CO2)=12+16*2=44 г/моль
n(CO2)=2/44=0,045 моль
V(CO2)=0,045*22,4=1,008 л