Мr(BaO)=Ar(Ba)+Ar(O)=137+16=153.
Mr(H2CO3)=2Ar(H)+Ar(C)+3Ar(O)=2*1+12+3*16=2+12+48=62.
Mr(CuSO4)=Ar(Cu)+Ar(S)+4Ar(O)=64+32+4*16=64+32+64=160.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Мr(BaO)=Ar(Ba)+Ar(O)=137+16=153.
Mr(H2CO3)=2Ar(H)+Ar(C)+3Ar(O)=2*1+12+3*16=2+12+48=62.
Mr(CuSO4)=Ar(Cu)+Ar(S)+4Ar(O)=64+32+4*16=64+32+64=160.