ВНИМАНИЕ, второй раз задаю
Be(OH)2 + NaOH -------->(сплавление)
Be(OH)2 + HCl ??
Be(OH)2 + NaOH -------->(сплавление)
Be(OH)2 + HCl ??
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Be(OH)2 + 2NaOH = Na2BeO2 + 2H2OBe(OH)2 + 2HCl = BeCl2 + 2H2O