Во вложении помогите сроччно. Created by arsen01. matematika-ru

Во вложении помогите сроччно...

arsen01 @arsen01

July 2022 1 14 Report

Во вложении помогите сроччно

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VekaSolnce

$(\sqrt{15}+\sqrt{10})*2\sqrt{5}-5\sqrt{12}=\sqrt{15}*2\sqrt{5}+\sqrt{10}*2\sqrt{5}-5\sqrt{12}=$

$=\sqrt{3}*\sqrt{5}*2\sqrt{5}+\sqrt{2}*\sqrt{5}*2\sqrt{5}-5\sqrt{4}*\sqrt{3}=$

$=10\sqrt{3}+10\sqrt{2}-10\sqrt{3}=10\sqrt{2}$

$\frac{2\sqrt{70}-2\sqrt{28}}{3\sqrt{35}-3\sqrt{14}}=\frac{2\sqrt{2}\sqrt{35}-2\sqrt{2}\sqrt{14}}{3\sqrt{35}-3\sqrt{14}}=\frac{2\sqrt{2}(\sqrt{35}-\sqrt{14})}{3\sqrt{35}-3\sqrt{14}}=\frac{2\sqrt{2}}{3}$

$(2\sqrt{12}-3\sqrt{3})^{2}=4*12-2*2\sqrt{12}*3\sqrt{3}+9*3=$

$48-12\sqrt{36}+27=48-72+27=3$

$\frac{10-5\sqrt{3}}{10+5\sqrt{3}}+\frac{10+5\sqrt{3}}{10-5\sqrt{3}}=\frac{(10-5\sqrt{3})^2+(10+5\sqrt{3})^2}{(10+5\sqrt{3})*(10-5\sqrt{3})}=$

$=\frac{100-10\sqrt{3}+75+100+10\sqrt{3}+75}{100-75}=\frac{350}{25}=14$

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napishite v molekulyarnompolnom i sokrashennom ionnom vide uravneniya reakcii sogla

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arsen01 August 2021 | 0 Ответы

1zakonchite uravnenie reakcij achobsovfeo2kakoj obem kislorod

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