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ArianatorLove
@ArianatorLove
August 2021
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Godnessgirl
пусть
получим
t²-8t+12=0
D=64-4*12=64-48=16=4²
t1=(8-4)/2=2
t2=(8+4)/2=6
возвращаемся к замене
2^х=2
х=1
2^х=6
х=log(6) по основанию 2
0 votes
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ArianatorLove
Оно должно иметь корни
ArianatorLove
Там х+3 оказалось, решт пожалуйста
Godnessgirl
ок
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Answers & Comments
пусть
получим
t²-8t+12=0
D=64-4*12=64-48=16=4²
t1=(8-4)/2=2
t2=(8+4)/2=6
возвращаемся к замене
2^х=2
х=1
2^х=6
х=log(6) по основанию 2