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Mechtatelnica1997
@Mechtatelnica1997
July 2022
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Возведите в степень комплексные числа.
(1-i)8 (8-степень)
(1+i) -3 (-3-степень)
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Lumenious
1) = 0 т.к. i^8=1 т.е. 1-1=0
2)=1/(1-i) т.к. x^-3=1/x^3 i^3=-i
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Answers & Comments
2)=1/(1-i) т.к. x^-3=1/x^3 i^3=-i