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AlekseyKa1998
@AlekseyKa1998
October 2021
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4362482
Ничегго не знаююю труляля труляля все эти ведб три рубля
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girl2303
1.
a) 4x² - 81 = (2x - 9)(2x + 9)
б) (2x + 1)² - 16 = 4x² + 4x +1 - 16 = 4x² + 4x - 15
в) (2x - 3)(2x + 3) - (2x - 1)² = (2x - 3)(2x + 3) - (4x² - 4x + 1) = 4x² - 9 - 4x² + 4x - 1 = 4x - 10 = 2(2x - 5)
2.
a) x⁴ - 9 = (x² - 3)(x² + 3)
б) 125a³ - 1/64c³ = (5a - 1/4c)(25c² + 1,25ac + 1/16c²)
3.
(7 - x)² - (x - 8)(x + 8) = 43
49 - 14x + x² - (x² - 64) = 43
49 - 14x + x² - x² + 64 = 43
- 14x + 113 = 43
- 14x = 43 - 113
- 14x = - 70
x = 5
Ответ: 5
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Answers & Comments
a) 4x² - 81 = (2x - 9)(2x + 9)
б) (2x + 1)² - 16 = 4x² + 4x +1 - 16 = 4x² + 4x - 15
в) (2x - 3)(2x + 3) - (2x - 1)² = (2x - 3)(2x + 3) - (4x² - 4x + 1) = 4x² - 9 - 4x² + 4x - 1 = 4x - 10 = 2(2x - 5)
2.
a) x⁴ - 9 = (x² - 3)(x² + 3)
б) 125a³ - 1/64c³ = (5a - 1/4c)(25c² + 1,25ac + 1/16c²)
3.
(7 - x)² - (x - 8)(x + 8) = 43
49 - 14x + x² - (x² - 64) = 43
49 - 14x + x² - x² + 64 = 43
- 14x + 113 = 43
- 14x = 43 - 113
- 14x = - 70
x = 5
Ответ: 5