все что отмечено карандашом!Пожалуйста помогите:). Created by izabella9731. algebra-ru

5) у=2√х + √(3х-х²-2) х-4{x≥0{x-4≠0{3x-x²-2≥0x-4≠0x≠43x-x²-2≥0x²-3x+2≤0Парабола-ветви вверх.х²-3х+2=0Д=9-8=1х₁=3-1=1 2х₂=3+1=2 2 + \\\\\\\\\\ +------ 1 ---------- 2 --------- -х∈[1; 2]{x≥0{x≠4{x∈[1; 2] \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\---- 0 ------ 1 -------- 2 ------- 4 -------- \\\\\\\\\\х∈[1;2]D(y)=[1; 2] - область определения функции6) у=√х + √(1/(х-2)){x≥0{ 1 >0 x-2 1 >0 x-2x-2>0x>2{x≥0{x>2 \\\\\\\\\\\\\\\\\\\\\\\\\-------- 0 ------- 2 --------- \\\\\\\\\\\\\\\\\\\\x∈(2; +∞)D(y)=(2; +∞)спасибо большое) Новые вопросы в АлгебраЗнайдіть рiвняння горизонтальних дотичних до графіка функції f(x)=x⁴ - 4x²-8.y = 5|x| - 5Помогите решить! График функций!y = 3x - |x| - 1Помогите решить! График функций!y = |x| + xПомогите решить! График функций!y = -|x|Помогите решить! График функций!y = 2x + 3|x|-2Помогите решить! График функций!y = 2*|x|+2Помогите решить! 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все что отмечено карандашом!Пожалуйста помогите:)...

izabella9731 @izabella9731

August 2022 1 7 Report

все что отмечено карандашом!Пожалуйста помогите:)

Answers & Comments

m11m 5) у=2√х + √(3х-х²-2)
  х-4
{x≥0
{x-4≠0
{3x-x²-2≥0

x-4≠0
x≠4

3x-x²-2≥0
x²-3x+2≤0
Парабола-ветви вверх.
х²-3х+2=0
Д=9-8=1
х₁=3-1=1
2
х₂=3+1=2
2
+ \\\\\\\\\\ +
------ 1 ---------- 2 ---------
-
х∈[1; 2]

{x≥0
{x≠4
{x∈[1; 2]
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
---- 0 ------ 1 -------- 2 ------- 4 --------
\\\\\\\\\\
х∈[1;2]
D(y)=[1; 2] - область определения функции

6) у=√х + √(1/(х-2))
{x≥0
{ 1 >0
x-2

1 >0
  x-2
x-2>0
x>2

{x≥0
{x>2
\\\\\\\\\\\\\\\\\\\\\\\\\
-------- 0 ------- 2 ---------
  \\\\\\\\\\\\\\\\\\\\
x∈(2; +∞)
D(y)=(2; +∞)