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Данякеп
@Данякеп
August 2022
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oganesbagoyan
Verified answer
Task/26548526
--------------------
17.
12 / (sin²37°+sin²127°)
=12
/
(sin²37°+sin²(90° +37°) =12
/
(sin²37°+cos²37°) =
12 /1
=12.
--------------
18
.
6 /(cos
²23
°
+cos²113
°
)
=
6
/(
cos²23°+cos²(90° +23°)
)
=
6
/
(cos²23° +sin²23°) = 6/1
=6.
--------------
19
.
12/ (sin²27
° + cos
²207
°)
=12/
(
sin²27°+ cos²(180° +27
°)
)
=
12
/
(sin²27° +cos²27
°) =12/1
=12.
* * * cos(180 ° +27°) = -cos27° ; cos²(180 ° +27°) = (-cos27°)² =cos²27
° * * *
Все примеры можно решать по другому
--------------
например 17
.
12
/
(sin²37°+sin²127°) = 12/( (1-cos2*37°) /2 +(1- cos2*
127°)/2 ) =
-6 / ( cos74°+ cos254° -2
) =
-6 /
(
2cos(254 -74)/2 *cos(254 +74)/2 -2
)
=
-6(
cos90°
*cos164° -2) = -6 *(0 -2)
= 12.
2 votes
Thanks 1
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Answers & Comments
Verified answer
Task/26548526--------------------
17.
12 / (sin²37°+sin²127°) =12 / (sin²37°+sin²(90° +37°) =12 / (sin²37°+cos²37°) =
12 /1 =12.
--------------
18.
6 /(cos²23° +cos²113°)=6 /( cos²23°+cos²(90° +23°) ) =6 /(cos²23° +sin²23°) = 6/1 =6.
--------------
19.
12/ (sin²27° + cos²207°) =12/ ( sin²27°+ cos²(180° +27°) ) =
12/(sin²27° +cos²27°) =12/1 =12.
* * * cos(180 ° +27°) = -cos27° ; cos²(180 ° +27°) = (-cos27°)² =cos²27° * * *
Все примеры можно решать по другому
--------------
например 17.
12 / (sin²37°+sin²127°) = 12/( (1-cos2*37°) /2 +(1- cos2*127°)/2 ) =
-6 / ( cos74°+ cos254° -2 ) = -6 / (2cos(254 -74)/2 *cos(254 +74)/2 -2 ) =
-6( cos90°*cos164° -2) = -6 *(0 -2) = 12.