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coffee4202
@coffee4202
July 2022
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второе задание,,,,,,
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anassstass
Дано:
m (CuSO4) = 160 г
CuSO4 + KOH — ?
w (вых) = 80%
Найти: m (Cu(OH)2) - ?
Решение:
M (CuSO4) = 64 + 32 + 64 = 160 г/моль
n (CuSO4) = m/M = 160 г / 160 г/моль = 1 моль
CuSO4 + 2KOH — K2SO4 + Cu(OH)2
n (Cu(OH)2) = n (CuSO4) = 1 моль
M (Cu(OH)2) = 64 + 32 + 2 = 98 г/моль
m (теорет. Cu(OH)2) = 98 г/моль • 1 моль = 98 г
m (практ. Cu(OH)2) = 98 г • 0,8 = 78,4 г
Ответ: 78,4 г
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Answers & Comments
m (CuSO4) = 160 г
CuSO4 + KOH — ?
w (вых) = 80%
Найти: m (Cu(OH)2) - ?
Решение:
M (CuSO4) = 64 + 32 + 64 = 160 г/моль
n (CuSO4) = m/M = 160 г / 160 г/моль = 1 моль
CuSO4 + 2KOH — K2SO4 + Cu(OH)2
n (Cu(OH)2) = n (CuSO4) = 1 моль
M (Cu(OH)2) = 64 + 32 + 2 = 98 г/моль
m (теорет. Cu(OH)2) = 98 г/моль • 1 моль = 98 г
m (практ. Cu(OH)2) = 98 г • 0,8 = 78,4 г
Ответ: 78,4 г