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viko123i
@viko123i
August 2022
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Вычеслить массовую долю оксигена в таких соединениях: Ca (OH) во 2, FeCo в 3 Zn (NO в 3) во 2
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svetka1574
Mr(CaCO3) = 40 + 12 + 16*3 = 100
W(O) = Ar(O)*n / Mr(CaCO3) *100% = 16*3 / 100 *100% = 48%
Mr(FeCO3) = 56 + 12 + 16*3 = 116
W(O) = Ar(O) *n / Mr(FeCO3) *100% = 16*3 / 116 *100% = 41%
Mr(Zn(NO3)2 = 65 + 14*2 + 16*6 = 189
W(O) = Ar(O) * n / Mr(Zn(NO3)2) *100% = 16*6 / 189 *100% =51%
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Answers & Comments
W(O) = Ar(O)*n / Mr(CaCO3) *100% = 16*3 / 100 *100% = 48%
Mr(FeCO3) = 56 + 12 + 16*3 = 116
W(O) = Ar(O) *n / Mr(FeCO3) *100% = 16*3 / 116 *100% = 41%
Mr(Zn(NO3)2 = 65 + 14*2 + 16*6 = 189
W(O) = Ar(O) * n / Mr(Zn(NO3)2) *100% = 16*6 / 189 *100% =51%