Ответ:

дано

m(ZnCL2) = 70 g

m(H3PO4) = 50 g

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m(Zn3(PO4)2)-?

M(ZnCL2) = 136 g/mol

n(ZnCL2) = m/M = 70 / 136 = 0.5147 mol

M(H3PO4) = 98 g/mol

n(H3PO4) = m/M = 50 / 98 = 0.51 mol

n(ZnCL2) > n(H3PO4)

3ZnCL2 + 2H3PO4-->Zn3(PO4)2+6HCL

M(Zn3(PO4)2) = 385 g/mol

2n(H3PO4) = n(Zn3(PO4)2)

n(Zn3(PO4)2) = 0.51 / 2 = 0.255 mol

m(Zn3(PO4)2) = n*M = 0.255 * 385 = 98.175 g

ответ 98.175 г

Объяснение: