вычеслите координаты точек пересечения прямых x+3y=-12 4x-6y=-12
{x+3y=-12
{4x-6y=-12
{x+3y=4x-6y
{3x-9y=0
{x-3y=0
{3y+3y=-12 {6y=-12
{y=-2
{x=-6
Составляем систему:
x+3y=-12 x=-12-3y x=-12-3*(-2)=-12+6=-6
4x-6y=-12 4(-12-3y)-6y=-12 y=-2
-48-12y-6y=-12
-18y=-12+48
-18y=36
y=-2
A(-6;-2)
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Verified answer
{x+3y=-12
{4x-6y=-12
{x+3y=4x-6y
{3x-9y=0
{x-3y=0
{x-3y=0
{x+3y=-12
{3y+3y=-12
{6y=-12
{y=-2
{x=-6