Ответ:
sin15°- sin75°= A(альфа)-В(бета) A+B
2sin ------------------------- * cos --------------
2 2
15-75 15-75
=2sin---------------- * cos------------- = 2sin45° * cos(-60)=
√2 1
=2* ------ * cos ----- = √2 * cos1/2
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Ответ:
sin15°- sin75°= A(альфа)-В(бета) A+B
2sin ------------------------- * cos --------------
2 2
15-75 15-75
=2sin---------------- * cos------------- = 2sin45° * cos(-60)=
2 2
√2 1
=2* ------ * cos ----- = √2 * cos1/2
2 2