Ответ:
KOH+AI(OH)3=K[AI(OH)4]
v(Al(oh)3)=7.8/78=0.1mol
m(KOH)=0.1*56=5.6g
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Ответ:
KOH+AI(OH)3=K[AI(OH)4]
v(Al(oh)3)=7.8/78=0.1mol
m(KOH)=0.1*56=5.6g