Zn+2HCl=ZnCl₂+H₂
V(H₂)=1.12л
n(H₂)=1.12л÷22.4л/моль=0.05/моль
n(Zn)=0.05/моль
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Zn+2HCl=ZnCl₂+H₂
V(H₂)=1.12л
n(H₂)=1.12л÷22.4л/моль=0.05/моль
n(Zn)=0.05/моль