Ответ:
ZN+H2SEO4=ZnSeO4+h2
v(zn)=45.5/65=0.7mol
v(zn)=v(h2)
V(h2)=0.7*22.4=15.68l
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Ответ:
ZN+H2SEO4=ZnSeO4+h2
v(zn)=45.5/65=0.7mol
v(zn)=v(h2)
V(h2)=0.7*22.4=15.68l